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#summation — Public Fediverse posts

Live and recent posts from across the Fediverse tagged #summation, aggregated by home.social.

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  1. Opendoor co-founder brings Seattle-area startup Summation out of stealth with $35M in funding - Summation co-founders Ramachandran “RC” Ramarathinam (left) and Ian Wong. (Summat... - geekwire.com/2025/opendoor-co- #summation #startups #funding #ianwong

  2. CW: BDSM

    #Auction: furaffinity.net/view/59414213/

    - SB per slot is $80 and AB $350
    - AB for the complete piece is $600
    - The minimum bid is $ 10
    - The auction ends on January 12 at 11 pm (GMT-3)
    - Any species

    #male #summation #domination #gay #ych #mind_control #roleplay #pet

  3. CW: BDSM - chastity

    Commission YCH for Kodi_husky437
    A quiet afternoon of training >:3

    Thank you very much for supporting my art by participating in this drawing. =D

    (My FA: furaffinity.net/user/dingodieg)

    #male #summation #domination #size_difference #wolf #husky #fanart #kody #balto #bondage #BDSM #cage #chastity #pets #furryart

  4. CW: BDSM - chastity

    You can participate in the auction on the FA page or directly by leaving a comment here with your offer.
    I will keep the offers updated on both sites.

    - Minimum bid is $ 10
    - The auction ends on October 5 at 11 pm (GMT-3)
    - Any species

    furaffinity.net/view/58292731/

    #male #dick #summation #domination #size_difference #auction #ych #bondage #BDSM #cage #ball_gag

  5. @zvavybir
    It does diverge. It has no sum.
    However, the uniquely valued #Riemann #ZetaFunction can be analytically continued into the left half-plane where we find zeta(-1)=-1/12 (which 'looks like' 1+2+...). #Cesàro #summation will get you part of the way there also, and, as you say, yields the same result; presumably due to some ultimate cosmic logical rightness :-)
    I very strongly recommend BP's superb exposition of this issue
    youtube.com/watch?v=YuIIjLr6vU
    #maths #AnalyticContinuation #Ramanujan

  6. Try to prove the following two results that relate the harmonic numbers to the golden ratio. Have an excellent weekend.

    \[\displaystyle\sum_{n=1}^\infty\binom{2n}n\dfrac{H_n}{5^n}=2\sqrt5\ln\varphi\]

    \[\displaystyle\sum_{n=1}^\infty\binom{2n}n\dfrac{H_n}{5^nn}=\frac{2\pi^2}{15}-2\ln^2\varphi\]

    where \(\varphi=\frac{1+\sqrt5}2\) is the golden ratio; and \(H_n=\left(1+\frac12+\frac13+\ldots+\frac1n\right)\) is the \(n\)-th harmonic number.

    #GoldenRatio #HarmonicNumbers #HarmonicNumber #Logarithm #Pi #Summation #Math #Sum #InfiniteSum #Binomial #BinomialCoefficient #Maths #WeekendChallenge