#eulernumber — Public Fediverse posts
Live and recent posts from across the Fediverse tagged #eulernumber, aggregated by home.social.
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I gave this integral as an answer at MathSE.
\[\int_{0}^{1}\left(\frac{5}{2} \left((x - \sqrt{x^2 - 1})^{2i} + x^4\right)-1\right)\,dx=e^\pi.\]
The integral yields \(e^{\pi}\). I don't know why the LaTeX isn't displaying properly.
#math #integral #eulernumber #halfangleapproach #symmetrymatters #calculus
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I gave this integral as an answer at MathSE.
\[\int_{0}^{1}\left(\frac{5}{2} \left((x - \sqrt{x^2 - 1})^{2i} + x^4\right)-1\right)\,dx=e^\pi.\]
The integral yields \(e^{\pi}\). I don't know why the LaTeX isn't displaying properly.
#math #integral #eulernumber #halfangleapproach #symmetrymatters #calculus
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I gave this integral as an answer at MathSE.
\[\int_{0}^{1}\left(\frac{5}{2} \left((x - \sqrt{x^2 - 1})^{2i} + x^4\right)-1\right)\,dx=e^\pi.\]
The integral yields \(e^{\pi}\). I don't know why the LaTeX isn't displaying properly.
#math #integral #eulernumber #halfangleapproach #symmetrymatters #calculus
-
I gave this integral as an answer at MathSE.
\[\int_{0}^{1}\left(\frac{5}{2} \left((x - \sqrt{x^2 - 1})^{2i} + x^4\right)-1\right)\,dx=e^\pi.\]
The integral yields \(e^{\pi}\). I don't know why the LaTeX isn't displaying properly.
#math #integral #eulernumber #halfangleapproach #symmetrymatters #calculus
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Deleting #ephipi cruft. The first #Perl script I'm sticking with (which I've renamed ePhiPi_0xMagBin.pl) is the poor man's stress test. All it does it examine the constants #EulerNumber, #Phi, and #pi for matching single binary digits or strings of digits by orders of 0x magnitude. It reaches the 7th fairly quickly.